Solution to Exercise 1.41:
(define (double f)
(lambda (x) (f (f x))))
Output:
> (define (inc x) (+ x 1))
> (((double (double double)) inc) 5)
21
Solution to Exercise 1.41:
(define (double f)
(lambda (x) (f (f x))))
Output:
> (define (inc x) (+ x 1))
> (((double (double double)) inc) 5)
21