Solution to Exercise 1.3:

`(define (square x)`

(* x x))

```
```(define (sum-of-squares x y)

(+ (square x) (square y)))

`(define (sum-of-squares-of-two-larger x y z)`

(cond ((and (<= x y) (<= x z)) (sum-of-squares y z))

((and (<= y x) (<= y z)) (sum-of-squares x z))

(else (sum-of-squares x y))))